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Take a linear factor common to a sum below the bar out of it - #1932
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Rafael-SOWNet merged 3 commits intoOct 17, 2026
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1/(a x + b x/ln(c x^n)^k) is 1/(x (a + b/ln(c x^n)^k)), a function of the logarithm beside its differential, which is answered in a tenth of a second; as written it was left unevaluated (Rubi's 3.5:323-326). Co-Authored-By: Claude Opus 5.5 (1M context) <noreply@anthropic.com> Claude-Session: https://claude.ai/code/session_012sonx8iAspMiwRwokT1Ura
…tor-of-a-sum-below-the-bar-is-taken-out
Co-Authored-By: Claude Opus 5.5 (1M context) <noreply@anthropic.com> Claude-Session: https://claude.ai/code/session_012sonx8iAspMiwRwokT1Ura
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October 29, 2026 00:43
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Part of #718.
1/(a x + b x/log(c x^n))was left unevaluated, while1/(x (a + b/log(c x^n))), the same integrand with x taken out of the sum below the bar, is answered in a tenth of a second as a function of the logarithm beside its differential. The existingSolveByGatheringACommonPolynomialFactorOfASumalready takes a common power of a linear out of a sum that is the whole integrand. This does the same for a sum below the bar, alone or to a whole power, dispatched right after it.Rubi corpus, against master 081b56f (budget 5 s):
1/(a x + b x/log(c x^n))… /log(c x^n)^2… /log(c x^n)^3… /log(c x^n)^4(a x + 2 b n log(c x^n))/(a x^2 + b x log(c x^n)^2)log(a x + b log(c x^n)^2))The other rows that moved:
tanh(a + 2 log(x))^2/x^3is still answered, now in 0.5 s rather than 4.4 s. Its answer is 7,796 characters against master's 4,078: the tanh's exponential form has a sum with a commonx^2below the bar. 2.5.0 left it unevaluated, and it is recorded with the others.Family 3 whole is the pocket. Family 0 whole and families 1–8 sampled show no losses and no wrong answers. The allocation gate and the suite pass.
🤖 Generated with Claude Code
https://claude.ai/code/session_012sonx8iAspMiwRwokT1Ura